In the Select() query, a lambda expression will be utilized.

c# expression-trees lambda


I am trying to build a lambda expression, containing two assignments (as shown further down), that I can then pass to a Queryable.Select() method.

I am trying to pass a string variable into a method and then use that variable to build up the lambda expression so that I can use it in a LINQ Select query.

My reasoning behind it is that I have a SQL Server datasource with many column names, I am creating a charting application that will allow the user to select, say by typing in the column name, the actual column of data they want to view in the y-axis of my chart, with the x-axis always being the DateTime. Therefore, they can essentially choose what data they chart against the DateTime value (it’s a data warehouse type app).

I have, for example, a class to store the retrieved data in, and hence use as the chart source of:

public class AnalysisChartSource
    public DateTime Invoicedate { get; set; }
    public Decimal yValue { get; set; }

I have (purely experimentaly) built an expression tree for the Where clause using the String value and that works fine:

public void GetData(String yAxis)
    using (DataClasses1DataContext db = new DataClasses1DataContext())
        var data = this.FunctionOne().AsQueryable<AnalysisChartSource>();
        //just to get some temp data in....

        ParameterExpression pe = Expression.Parameter(typeof(AnalysisChartSource), "p");
        Expression left = Expression.MakeMemberAccess(pe,
        Expression right = Expression.Constant((Decimal)16);
        Expression e2 = Expression.LessThan(left, right);
        Expression expNew = Expression.New(typeof(AnalysisChartSource));

        LambdaExpression le = Expression.Lambda(left, pe);

        MethodCallExpression whereCall = Expression.Call(
            typeof(Queryable), "Where", new Type[] { data.ElementType },
            Expression.Lambda<Func<AnalysisChartSource, bool>>(e2, new ParameterExpression[] { pe }));

However……I have tried a similar approach for the Select statement, but just can’t get it to work as I need the Select() to populate both X and Y values of the AnalysisChartSource class, like this:

.Select(c => new AnalysisChartSource 
{ Invoicedate = c.Invoicedate, yValue = c.yValue}).AsEnumerable();

How on earth can I build such an expression tree….or….possibly more to the point… there an easier way that I have missed entirely?

4/27/2010 8:36:10 AM

Accepted Answer

I find that the best way to work out how to build expression trees is to see what the C# compiler does. So here's a complete program:

using System;
using System.Linq.Expressions;

public class Foo
    public int X { get; set; }
    public int Y { get; set; }

class Test
    static void Main()
        Expression<Func<int, Foo>> builder = 
            z => new Foo { X = z, Y = z };

Compile that, open the results in Reflector and set the optimisation to .NET 2.0. You end up with this generated code for the Main method:

ParameterExpression expression2;
Expression<Func<int, Foo>> expression = 
  Expression.Lambda<Func<int, Foo>>(
      Expression.New((ConstructorInfo) methodof(Foo..ctor), new Expression[0]),
      new MemberBinding[] { Expression.Bind((MethodInfo) methodof(Foo.set_X),
                           expression2 = Expression.Parameter(typeof(int), "z")),
                           Expression.Bind((MethodInfo) methodof(Foo.set_Y), 
                                            expression2) }
    new ParameterExpression[] { expression2 });

Basically, I think Expression.MemberInit is what you're after.

4/27/2010 8:39:19 AM

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