Convert or Copy the Expression Tree

c# dynamic-language-runtime expression-trees lambda


How to convert a ExpressionTree of form

Expression<Func<POCO1, bool>> exp = p => p.Age > 50;


Expression<Func<POCO2, bool>> exp2 = p => p.Age > 50;

where POCO1 and POCO2 are C# objects and both have Int32 Age property

1/5/2011 7:49:15 AM

Accepted Answer

well, you can make custom expression visitor that will replace parameter references and patch member access expressions

class Converter<TTo>
    class ConversionVisitor : ExpressionVisitor
        private readonly ParameterExpression newParameter;
        private readonly ParameterExpression oldParameter;

        public ConversionVisitor(ParameterExpression newParameter, ParameterExpression oldParameter)
            this.newParameter = newParameter;
            this.oldParameter = oldParameter;

        protected override Expression VisitParameter(ParameterExpression node)
            return newParameter; // replace all old param references with new ones

        protected override Expression VisitMember(MemberExpression node)
            if (node.Expression != oldParameter) // if instance is not old parameter - do nothing
                return base.VisitMember(node);

            var newObj = Visit(node.Expression);
            var newMember = newParameter.Type.GetMember(node.Member.Name).First();
            return Expression.MakeMemberAccess(newObj, newMember);

    public static Expression<Func<TTo, TR>> Convert<TFrom, TR>(
        Expression<Func<TFrom, TR>> e
        var oldParameter = e.Parameters[0];
        var newParameter = Expression.Parameter(typeof(TTo), oldParameter.Name);
        var converter = new ConversionVisitor(newParameter, oldParameter);
        var newBody = converter.Visit(e.Body);
        return Expression.Lambda<Func<TTo, TR>>(newBody, newParameter);

class A
    public int Value { get; set; }

class B
    public int Value { get; set; }

Expression<Func<A, int>> f = x => x.Value;
var f2 = Converter<B>.Convert(f);
1/5/2011 9:32:32 AM

Popular Answer

Rough Steps:

 Get the expression Cast it to BinaryExpression
 Get the left operand Cast it to MemberExpression
 Get the Underlying Type that the property belong to 
 Change it to your new type if you can.

The type you get here is a property without setter as I guessed.

Expression<Func<MainWindow, bool >> exp1 = o => this.ActualHeight>50;
var type = ((MemberExpression)((BinaryExpression)exp1.Body).Left).Expression.Type;

So you must build a new expression

Here is the way

manually build linq expression for x => x.Child == itemToCompare.Child

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