to string expression

c# expression expression-trees


How can I get a string like


from the expression as demoed in this snip it:

IMyService myService = ...;
int param1 = 1;

myExpressionService.Get(c => myService.Do(param1));

I actually don't want to call Do unless a condition is met using the string that was generated.

3/21/2011 10:12:38 PM

Accepted Answer

You will have to traverse Expression trees. Here is some sample code:

internal static class myExpressionService
    public static string Get(Expression<Action> expression)
        MethodCallExpression methodCallExpression = (MethodCallExpression)expression.Body;
        var method = methodCallExpression.Method;
        var argument = (ConstantExpression) methodCallExpression.Arguments.First();

        return string.Format("{0}.{1}({2})", method.DeclaringType.FullName, method.Name, argument.Value);

It works if called in this way: string result = myExpressionService.Get(() => myService.Do(1));

The output is: Namespace.IMyService.Do(1)

You can extend/update it to handle your scenario.

3/21/2011 10:43:29 PM

Popular Answer

This would also work (though it's not particularly elegant):

public static string MethodCallExpressionRepresentation(this LambdaExpression expr)
    var expression = (MethodCallExpression)expr.Body;

    var arguments = string.Join(", ", expression.Arguments.OfType<MemberExpression>().Select(x => {
        var tempInstance = ((ConstantExpression)x.Expression).Value;
        var fieldInfo = (FieldInfo)x.Member;
        return "\"" + fieldInfo.GetValue(tempInstance).ToString() + "\"";

    return expression.Object.Type.FullName + "." + expression.Method.Name + "(" + arguments + ")";

You can call it like this:

Expression<Action> expr = c => myService.Do(param1));
var repr = expr.MethodCallExpressionRepresentation();    // Namespace.IMyService.Do("1")

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