I want to create lambda expression providing property name, a value (as string) and property type (as Type).
The problem with that is in line Expression.Constant(value1, propertyType);
value1 that is passed to Foo is string. and must be parsed to "unknown" type
static Expression<Func<T, bool>> LabmdaExpression<T>(string property1, string value1,
Type propertyType)
{
var parameterExpression = Expression.Parameter(typeof(TheObject), "o");
var memberExpression1 = Expression.PropertyOrField(parameterExpression, property1);
//casting?
var valueExpression1 = Expression.Constant(value1, propertyType);
var binaryExpression1 = Expression.GreaterThan(memberExpression1, valueExpression1);
return Expression.Lambda<Func<T, bool>>(binaryExpression1, parameterExpression);
}
I think you should have T
where you currently have TheObject
.
To convert the string, you can call the Convert.ChangeType()
method in your expression and cast the resulting object:
static readonly MethodInfo ChangeTypeMethod = typeof(Convert).GetMethod(
"ChangeType", new[] { typeof(object), typeof(Type) });
static Expression<Func<T, bool>> LabmdaExpression<T>(
string property1, string value1, Type propertyType)
{
ParameterExpression parameterExpression = Expression.Parameter(typeof(T), "o");
MemberExpression memberExpression1 = Expression.PropertyOrField(
parameterExpression, property1);
Expression convertedObject = Expression.Call(
ChangeTypeMethod, Expression.Constant(value1),
Expression.Constant(propertyType));
Expression converted = Expression.Convert(convertedObject, propertyType);
BinaryExpression binaryExpression1 = Expression.GreaterThan(
memberExpression1, converted);
return Expression.Lambda<Func<T, bool>>(binaryExpression1, parameterExpression);
}
Just casting won't work, because code like (int)"42"
is not valid.