Expression. The simplest "Where" example using Lambda and query creation at runtime

.net c# dynamic-language-runtime expression-trees lambda


I was trying to generate a simple Lambda Expression at runtime with no luck... something like this:

var result = queryableData.Where(item => item.Name == "Soap")

Here is my example class and a fixture queryable:

public class Item
    public int Id { get; set; }
    public string Name { get; set; }

IQueryable<Item> queryableData = ...;

Then I generate a lambda expression at runtime correct code follows:

//"item" in "item =>..."
var item = Expression
    .Parameter(typeof(Item), "item");

//property of my item, this is "item.Name"
var prop = Expression
    .Property(item, "Name");

//then "Soap" in '... => item.Name=="Soap"'
var value = Expression.Constant("Soap");

//equality expression "==" in my primer
var equals = Expression.Equal(prop, value);

//then lambda
var lambda = Expression.Lambda<Func<Item, bool>>(equals, item);

//and here are the results    
var results = queryableData.Where(lambda);

Big thanks to dtb for advice!

11/29/2011 6:57:04 PM

Accepted Answer

In the following query

var result = query.Where(item => item.Name == "Soap")

the lambda expression is

item => item.Name == "Soap"

You only need to construct this part, not the Where call which accepts an expression tree.

The expression tree for the lambda expression looks like this:

                      /  \
                   Equal  Parameter
                   /   \    item
              Property  \
               "Name"   Constant
                 |       "Soap"

In code:

var item = Expression.Parameter(typeof(Item), "item");

var prop = Expression.Property(item, "Name");

var soap = Expression.Constant("Soap");

var equal = Expression.Equal(prop, soap);

var lambda = Expression.Lambda<Func<Item, bool>>(equal, item);

var result = queryableData.Where(lambda);
11/29/2011 6:36:30 PM

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