使用Select方法進行動態查詢和表達式樹

Question

使用Select方法進行動態查詢和表達式樹

c# exception-handling expression-trees linq

題

我試圖使用表達式樹創建一個動態查詢來匹配以下語句：

var items = data.Where(i => i.CoverageType == 2).Select(i => i.LimitSelected);

我可以創建where方法並從中獲取結果;但是，我無法創建select方法。

這是我的where方法：

var parm = Expression.Parameter(typeof(BaseClassData), "baseCoverage");

var queryData = data.AsQueryable();

var left = Expression.Property(parm, "CoverageType");
var right = Expression.Constant(2m);
var e1 = Expression.Equal(left, right);

var whereMethod = Expression.Call(
    typeof(Queryable), 
    "Where", 
    new Type[] { queryData.ElementType }, 
    queryData.Expression, 
    Expression.Lambda<Func<BaseClassData, bool>>(e1, new ParameterExpression[] { parm }));

這是我用於select方法的內容：

var selectParm = Expression.Property(parm, "LimitSelected");
     var selectMethod = Expression.Call(
        typeof(Enumerable),
        "Select",
        new Type[]{typeof(BaseClassData), typeof(decimal)},
        whereMethod,
        Expression.Lambda<Func<BaseClassData, decimal>>(selectParm, new ParameterExpression[]{ parm})

        );

當我運行代碼時，我收到此錯誤：

類型'System.Linq.Enumerable'上的通用方法'Select'與提供的類型參數和參數兼容。如果方法是非泛型的，則不應提供類型參數。

我也嘗試將Enumerable更改為Queryable，我得到了同樣的錯誤。

MarkSalow

在 Stack Overflow 上查看更多

Leng Weh Seng · Accepted Answer · 3/4/2013 11:05:46 AM

無需使用Expression.Call，您可以直接構造表達式樹;我創建了一個靜態方法來幫助我生成動態查詢：

public static void Test(string[] args) {
  using (var db = new DBContext()) {
    //query 1
    var query1 = db.PrizeTypes.Where(m => m.rewards == 1000).Select(t => t.name);

    //query 2 which equal to query 1
    Expression<Func<PrizeType, bool>> predicate1 = m => m.rewards == 1000;
    Expression<Func<PrizeType, string>> selector1 = t => t.name;
    var query2 = db.PrizeTypes.Where(predicate1).Select(selector1);
    Console.WriteLine(predicate1);
    Console.WriteLine(selector1);
    Console.WriteLine();

    //query 3 which equal to query 1 and 2
    Expression<Func<PrizeType, bool>> predicate2 = GetPredicateEqual<PrizeType>("rewards", (Int16)1000);
    Expression<Func<PrizeType, string>> selector2 = GetSelector<PrizeType, string>("name");
    var query3 = db.PrizeTypes.Where(predicate2).Select(selector2);
    Console.WriteLine(predicate2);
    Console.WriteLine(selector2);

    //as you can see, query 1 will equal query 2 equal query 3
  }
}

public static Expression<Func<TEntity, bool>> GetPredicateEqual<TEntity>(string fieldName, object fieldValue) where TEntity : class {
  ParameterExpression m = Expression.Parameter(typeof(TEntity), "t");
  var p = m.Type.GetProperty(fieldName);
  BinaryExpression body = Expression.Equal(
    Expression.Property(m, fieldName),
    Expression.Constant(fieldValue, p.PropertyType)
  );
  return Expression.Lambda<Func<TEntity, bool>>(body, m);
}

public static Expression<Func<T, TReturn>> GetSelector<T, TReturn>(string fieldName)
  where T : class
  where TReturn : class {
  var t = typeof(TReturn);
  ParameterExpression p = Expression.Parameter(typeof(T), "t");
  var body = Expression.Property(p, fieldName);
  return Expression.Lambda<Func<T, TReturn>>(body, new ParameterExpression[] { p });
}

使用Select方法進行動態查詢和表達式樹

題

Fastest Entity Framework Extensions

熱門答案

Performance

Expression Evaluator